7(2-(3+2x))-2x=-9+2(1-8x)

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Solution for 7(2-(3+2x))-2x=-9+2(1-8x) equation: 



7(2-(3+2x))-2x=-9+2(1-8x)

We move all terms to the left:

7(2-(3+2x))-2x-(-9+2(1-8x))=0

We add all the numbers together, and all the variables

7(2-(2x+3))-2x-(-9+2(-8x+1))=0

We add all the numbers together, and all the variables

-2x+7(2-(2x+3))-(-9+2(-8x+1))=0



We calculate terms in parentheses: -(-9+2(-8x+1)), so:

-9+2(-8x+1)

determiningTheFunctionDomain
2(-8x+1)-9

We multiply parentheses

-16x+2-9

We add all the numbers together, and all the variables

-16x-7

Back to the equation:

-(-16x-7)



We get rid of parentheses

-2x+7(2-(2x+3))+16x+7=0

We add all the numbers together, and all the variables

14x+7(2-(2x+3))+7=0

We move all terms containing x to the left, all other terms to the right

14x+7(2-(2x+3))=-7

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