7(2-(3+2x))-2x=-9+2(1-8x)

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Solution for 7(2-(3+2x))-2x=-9+2(1-8x) equation:



7(2-(3+2x))-2x=-9+2(1-8x)
We move all terms to the left:
7(2-(3+2x))-2x-(-9+2(1-8x))=0
We add all the numbers together, and all the variables
7(2-(2x+3))-2x-(-9+2(-8x+1))=0
We add all the numbers together, and all the variables
-2x+7(2-(2x+3))-(-9+2(-8x+1))=0
We calculate terms in parentheses: -(-9+2(-8x+1)), so:
-9+2(-8x+1)
determiningTheFunctionDomain 2(-8x+1)-9
We multiply parentheses
-16x+2-9
We add all the numbers together, and all the variables
-16x-7
Back to the equation:
-(-16x-7)
We get rid of parentheses
-2x+7(2-(2x+3))+16x+7=0
We add all the numbers together, and all the variables
14x+7(2-(2x+3))+7=0
We move all terms containing x to the left, all other terms to the right
14x+7(2-(2x+3))=-7

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