7(2-4(y-1))=7(2y+9)

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Solution for 7(2-4(y-1))=7(2y+9) equation: 



7(2-4(y-1))=7(2y+9)

We move all terms to the left:

7(2-4(y-1))-(7(2y+9))=0



We calculate terms in parentheses: -(7(2y+9)), so:

7(2y+9)

We multiply parentheses

14y+63

Back to the equation:

-(14y+63)



We get rid of parentheses

7(2-4(y-1))-14y-63=0

We add all the numbers together, and all the variables

-14y+7(2-4(y-1))-63=0

We move all terms containing y to the left, all other terms to the right

-14y+7(2-4(y-1))=63

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