7(2-5x)32=10x-3(6+15x)

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Solution for 7(2-5x)32=10x-3(6+15x) equation: 



7(2-5x)32=10x-3(6+15x)

We move all terms to the left:

7(2-5x)32-(10x-3(6+15x))=0

We add all the numbers together, and all the variables

7(-5x+2)32-(10x-3(15x+6))=0

We multiply parentheses

-1120x-(10x-3(15x+6))+448=0



We calculate terms in parentheses: -(10x-3(15x+6)), so:

10x-3(15x+6)

We multiply parentheses

10x-45x-18

We add all the numbers together, and all the variables

-35x-18

Back to the equation:

-(-35x-18)



We get rid of parentheses

-1120x+35x+18+448=0

We add all the numbers together, and all the variables

-1085x+466=0

We move all terms containing x to the left, all other terms to the right

-1085x=-466

x=-466/-1085

x=466/1085

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