7(2-x)+5-4(x-8)=-4-3(x+3)

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Solution for 7(2-x)+5-4(x-8)=-4-3(x+3) equation: 



7(2-x)+5-4(x-8)=-4-3(x+3)

We move all terms to the left:

7(2-x)+5-4(x-8)-(-4-3(x+3))=0

We add all the numbers together, and all the variables

7(-1x+2)-4(x-8)-(-4-3(x+3))+5=0

We multiply parentheses

-7x-4x-(-4-3(x+3))+14+32+5=0



We calculate terms in parentheses: -(-4-3(x+3)), so:

-4-3(x+3)

determiningTheFunctionDomain
-3(x+3)-4

We multiply parentheses

-3x-9-4

We add all the numbers together, and all the variables

-3x-13

Back to the equation:

-(-3x-13)



We add all the numbers together, and all the variables

-11x-(-3x-13)+51=0

We get rid of parentheses

-11x+3x+13+51=0

We add all the numbers together, and all the variables

-8x+64=0

We move all terms containing x to the left, all other terms to the right

-8x=-64

x=-64/-8

x=+8

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