7(20+3)=3(4d-7)

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Solution for 7(20+3)=3(4d-7) equation: 



7(20+3)=3(4d-7)

We move all terms to the left:

7(20+3)-(3(4d-7))=0

We add all the numbers together, and all the variables

-(3(4d-7))+723=0



We calculate terms in parentheses: -(3(4d-7)), so:

3(4d-7)

We multiply parentheses

12d-21

Back to the equation:

-(12d-21)



We get rid of parentheses

-12d+21+723=0

We add all the numbers together, and all the variables

-12d+744=0

We move all terms containing d to the left, all other terms to the right

-12d=-744

d=-744/-12

d=+62

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