7(2b-3)+6=-2(-6b-20)=1

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Solution for 7(2b-3)+6=-2(-6b-20)=1 equation: 



7(2b-3)+6=-2(-6b-20)=1

We move all terms to the left:

7(2b-3)+6-(-2(-6b-20))=0

We multiply parentheses

14b-(-2(-6b-20))-21+6=0



We calculate terms in parentheses: -(-2(-6b-20)), so:

-2(-6b-20)

We multiply parentheses

12b+40

Back to the equation:

-(12b+40)



We add all the numbers together, and all the variables

14b-(12b+40)-15=0

We get rid of parentheses

14b-12b-40-15=0

We add all the numbers together, and all the variables

2b-55=0

We move all terms containing b to the left, all other terms to the right

2b=55

b=55/2

b=27+1/2

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