7(2c+1)-(5+6c)+12=46

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Solution for 7(2c+1)-(5+6c)+12=46 equation: 



7(2c+1)-(5+6c)+12=46

We move all terms to the left:

7(2c+1)-(5+6c)+12-(46)=0

We add all the numbers together, and all the variables

7(2c+1)-(6c+5)+12-46=0

We add all the numbers together, and all the variables

7(2c+1)-(6c+5)-34=0

We multiply parentheses

14c-(6c+5)+7-34=0

We get rid of parentheses

14c-6c-5+7-34=0

We add all the numbers together, and all the variables

8c-32=0

We move all terms containing c to the left, all other terms to the right

8c=32

c=32/8

c=4

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