7(2c+4)=10(c+4)

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Solution for 7(2c+4)=10(c+4) equation:


Simplifying
7(2c + 4) = 10(c + 4)

Reorder the terms:
7(4 + 2c) = 10(c + 4)
(4 * 7 + 2c * 7) = 10(c + 4)
(28 + 14c) = 10(c + 4)

Reorder the terms:
28 + 14c = 10(4 + c)
28 + 14c = (4 * 10 + c * 10)
28 + 14c = (40 + 10c)

Solving
28 + 14c = 40 + 10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10c' to each side of the equation.
28 + 14c + -10c = 40 + 10c + -10c

Combine like terms: 14c + -10c = 4c
28 + 4c = 40 + 10c + -10c

Combine like terms: 10c + -10c = 0
28 + 4c = 40 + 0
28 + 4c = 40

Add '-28' to each side of the equation.
28 + -28 + 4c = 40 + -28

Combine like terms: 28 + -28 = 0
0 + 4c = 40 + -28
4c = 40 + -28

Combine like terms: 40 + -28 = 12
4c = 12

Divide each side by '4'.
c = 3

Simplifying
c = 3

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