7(2c-6)+11c=108

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Solution for 7(2c-6)+11c=108 equation: 



7(2c-6)+11c=108

We move all terms to the left:

7(2c-6)+11c-(108)=0

We add all the numbers together, and all the variables

11c+7(2c-6)-108=0

We multiply parentheses

11c+14c-42-108=0

We add all the numbers together, and all the variables

25c-150=0

We move all terms containing c to the left, all other terms to the right

25c=150

c=150/25

c=6

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