7(2f-4)=8(2f-1)

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Solution for 7(2f-4)=8(2f-1) equation: 



7(2f-4)=8(2f-1)

We move all terms to the left:

7(2f-4)-(8(2f-1))=0

We multiply parentheses

14f-(8(2f-1))-28=0



We calculate terms in parentheses: -(8(2f-1)), so:

8(2f-1)

We multiply parentheses

16f-8

Back to the equation:

-(16f-8)



We get rid of parentheses

14f-16f+8-28=0

We add all the numbers together, and all the variables

-2f-20=0

We move all terms containing f to the left, all other terms to the right

-2f=20

f=20/-2

f=-10

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