7(2k+4)-(3k+1)=49.

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Solution for 7(2k+4)-(3k+1)=49. equation: 



7(2k+4)-(3k+1)=49.

We move all terms to the left:

7(2k+4)-(3k+1)-(49.)=0

We add all the numbers together, and all the variables

7(2k+4)-(3k+1)-49=0

We multiply parentheses

14k-(3k+1)+28-49=0

We get rid of parentheses

14k-3k-1+28-49=0

We add all the numbers together, and all the variables

11k-22=0

We move all terms containing k to the left, all other terms to the right

11k=22

k=22/11

k=2

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