7(2k-4)-(3k+1)=49

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Solution for 7(2k-4)-(3k+1)=49 equation: 



7(2k-4)-(3k+1)=49

We move all terms to the left:

7(2k-4)-(3k+1)-(49)=0

We multiply parentheses

14k-(3k+1)-28-49=0

We get rid of parentheses

14k-3k-1-28-49=0

We add all the numbers together, and all the variables

11k-78=0

We move all terms containing k to the left, all other terms to the right

11k=78

k=78/11

k=7+1/11

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