7(2n+1)=7(6n+2)+2

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Solution for 7(2n+1)=7(6n+2)+2 equation:



7(2n+1)=7(6n+2)+2
We move all terms to the left:
7(2n+1)-(7(6n+2)+2)=0
We multiply parentheses
14n-(7(6n+2)+2)+7=0
We calculate terms in parentheses: -(7(6n+2)+2), so:
7(6n+2)+2
We multiply parentheses
42n+14+2
We add all the numbers together, and all the variables
42n+16
Back to the equation:
-(42n+16)
We get rid of parentheses
14n-42n-16+7=0
We add all the numbers together, and all the variables
-28n-9=0
We move all terms containing n to the left, all other terms to the right
-28n=9
n=9/-28
n=-9/28

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