7(2n+1)=8(9n+2)+7

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Solution for 7(2n+1)=8(9n+2)+7 equation: 



7(2n+1)=8(9n+2)+7

We move all terms to the left:

7(2n+1)-(8(9n+2)+7)=0

We multiply parentheses

14n-(8(9n+2)+7)+7=0



We calculate terms in parentheses: -(8(9n+2)+7), so:

8(9n+2)+7

We multiply parentheses

72n+16+7

We add all the numbers together, and all the variables

72n+23

Back to the equation:

-(72n+23)



We get rid of parentheses

14n-72n-23+7=0

We add all the numbers together, and all the variables

-58n-16=0

We move all terms containing n to the left, all other terms to the right

-58n=16

n=16/-58

n=-8/29

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