7(2n+3)=2(2n-2)

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Solution for 7(2n+3)=2(2n-2) equation: 



7(2n+3)=2(2n-2)

We move all terms to the left:

7(2n+3)-(2(2n-2))=0

We multiply parentheses

14n-(2(2n-2))+21=0



We calculate terms in parentheses: -(2(2n-2)), so:

2(2n-2)

We multiply parentheses

4n-4

Back to the equation:

-(4n-4)



We get rid of parentheses

14n-4n+4+21=0

We add all the numbers together, and all the variables

10n+25=0

We move all terms containing n to the left, all other terms to the right

10n=-25

n=-25/10

n=-2+1/2

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