7(2n+3)=2(6n+)

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Solution for 7(2n+3)=2(6n+) equation: 



7(2n+3)=2(6n+)

We move all terms to the left:

7(2n+3)-(2(6n+))=0

We add all the numbers together, and all the variables

7(2n+3)-(2(+6n))=0

We multiply parentheses

14n-(2(+6n))+21=0



We calculate terms in parentheses: -(2(+6n)), so:

2(+6n)

We multiply parentheses

12n

Back to the equation:

-(12n)



We add all the numbers together, and all the variables

2n+21=0

We move all terms containing n to the left, all other terms to the right

2n=-21

n=-21/2

n=-10+1/2

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