7(2n+3)=6(7n+2)+2

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Solution for 7(2n+3)=6(7n+2)+2 equation: 



7(2n+3)=6(7n+2)+2

We move all terms to the left:

7(2n+3)-(6(7n+2)+2)=0

We multiply parentheses

14n-(6(7n+2)+2)+21=0



We calculate terms in parentheses: -(6(7n+2)+2), so:

6(7n+2)+2

We multiply parentheses

42n+12+2

We add all the numbers together, and all the variables

42n+14

Back to the equation:

-(42n+14)



We get rid of parentheses

14n-42n-14+21=0

We add all the numbers together, and all the variables

-28n+7=0

We move all terms containing n to the left, all other terms to the right

-28n=-7

n=-7/-28

n=1/4

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