7(2n+4)+120=10(-(n+2))

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Solution for 7(2n+4)+120=10(-(n+2)) equation:


Simplifying
7(2n + 4) + 120 = 10(-1(n + 2))

Reorder the terms:
7(4 + 2n) + 120 = 10(-1(n + 2))
(4 * 7 + 2n * 7) + 120 = 10(-1(n + 2))
(28 + 14n) + 120 = 10(-1(n + 2))

Reorder the terms:
28 + 120 + 14n = 10(-1(n + 2))

Combine like terms: 28 + 120 = 148
148 + 14n = 10(-1(n + 2))

Reorder the terms:
148 + 14n = 10(-1(2 + n))
148 + 14n = 10((2 * -1 + n * -1))
148 + 14n = 10((-2 + -1n))
148 + 14n = (-2 * 10 + -1n * 10)
148 + 14n = (-20 + -10n)

Solving
148 + 14n = -20 + -10n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '10n' to each side of the equation.
148 + 14n + 10n = -20 + -10n + 10n

Combine like terms: 14n + 10n = 24n
148 + 24n = -20 + -10n + 10n

Combine like terms: -10n + 10n = 0
148 + 24n = -20 + 0
148 + 24n = -20

Add '-148' to each side of the equation.
148 + -148 + 24n = -20 + -148

Combine like terms: 148 + -148 = 0
0 + 24n = -20 + -148
24n = -20 + -148

Combine like terms: -20 + -148 = -168
24n = -168

Divide each side by '24'.
n = -7

Simplifying
n = -7

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