7(2p+3)-8=6p+28

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Solution for 7(2p+3)-8=6p+28 equation: 



7(2p+3)-8=6p+28

We move all terms to the left:

7(2p+3)-8-(6p+28)=0

We multiply parentheses

14p-(6p+28)+21-8=0

We get rid of parentheses

14p-6p-28+21-8=0

We add all the numbers together, and all the variables

8p-15=0

We move all terms containing p to the left, all other terms to the right

8p=15

p=15/8

p=1+7/8

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