7(2q+3)-3(a+5)=6

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Solution for 7(2q+3)-3(a+5)=6 equation:


Simplifying
7(2q + 3) + -3(a + 5) = 6

Reorder the terms:
7(3 + 2q) + -3(a + 5) = 6
(3 * 7 + 2q * 7) + -3(a + 5) = 6
(21 + 14q) + -3(a + 5) = 6

Reorder the terms:
21 + 14q + -3(5 + a) = 6
21 + 14q + (5 * -3 + a * -3) = 6
21 + 14q + (-15 + -3a) = 6

Reorder the terms:
21 + -15 + -3a + 14q = 6

Combine like terms: 21 + -15 = 6
6 + -3a + 14q = 6

Add '-6' to each side of the equation.
6 + -3a + -6 + 14q = 6 + -6

Reorder the terms:
6 + -6 + -3a + 14q = 6 + -6

Combine like terms: 6 + -6 = 0
0 + -3a + 14q = 6 + -6
-3a + 14q = 6 + -6

Combine like terms: 6 + -6 = 0
-3a + 14q = 0

Solving
-3a + 14q = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-14q' to each side of the equation.
-3a + 14q + -14q = 0 + -14q

Combine like terms: 14q + -14q = 0
-3a + 0 = 0 + -14q
-3a = 0 + -14q
Remove the zero:
-3a = -14q

Divide each side by '-3'.
a = 4.666666667q

Simplifying
a = 4.666666667q

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