7(2r-3)/3=7r-7/5

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Solution for 7(2r-3)/3=7r-7/5 equation: 


r in (-oo:+oo)

(7*(2*r-3))/3 = 7*r-(7/5) // - 7*r-(7/5)

(7*(2*r-3))/3-(7*r)+7/5 = 0

(7*(2*r-3))/3-7*r+7/5 = 0

(5*7*(2*r-3))/(3*5)+(-7*3*5*r)/(3*5)+(3*7)/(3*5) = 0

5*7*(2*r-3)-7*3*5*r+3*7 = 0

21-35*r-105 = 0

-35*r-84 = 0

(-35*r-84)/(3*5) = 0

(-35*r-84)/(3*5) = 0 // * 3*5

-35*r-84 = 0

-35*r-84 = 0 // + 84

-35*r = 84 // : -35

r = 84/(-35)

r = -12/5

r = -12/5

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