7(2r-5)=4r+10r+3+15

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Solution for 7(2r-5)=4r+10r+3+15 equation:


Simplifying
7(2r + -5) = 4r + 10r + 3 + 15

Reorder the terms:
7(-5 + 2r) = 4r + 10r + 3 + 15
(-5 * 7 + 2r * 7) = 4r + 10r + 3 + 15
(-35 + 14r) = 4r + 10r + 3 + 15

Reorder the terms:
-35 + 14r = 3 + 15 + 4r + 10r

Combine like terms: 3 + 15 = 18
-35 + 14r = 18 + 4r + 10r

Combine like terms: 4r + 10r = 14r
-35 + 14r = 18 + 14r

Add '-14r' to each side of the equation.
-35 + 14r + -14r = 18 + 14r + -14r

Combine like terms: 14r + -14r = 0
-35 + 0 = 18 + 14r + -14r
-35 = 18 + 14r + -14r

Combine like terms: 14r + -14r = 0
-35 = 18 + 0
-35 = 18

Solving
-35 = 18

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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