7(2r-5)=4r+5(2r+3)

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Solution for 7(2r-5)=4r+5(2r+3) equation: 



7(2r-5)=4r+5(2r+3)

We move all terms to the left:

7(2r-5)-(4r+5(2r+3))=0

We multiply parentheses

14r-(4r+5(2r+3))-35=0



We calculate terms in parentheses: -(4r+5(2r+3)), so:

4r+5(2r+3)

We multiply parentheses

4r+10r+15

We add all the numbers together, and all the variables

14r+15

Back to the equation:

-(14r+15)



We get rid of parentheses

14r-14r-15-35=0

We add all the numbers together, and all the variables

-50!=0

There is no solution for this equation

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