7(2t+1)+3f=55

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Solution for 7(2t+1)+3f=55 equation:


Simplifying
7(2t + 1) + 3f = 55

Reorder the terms:
7(1 + 2t) + 3f = 55
(1 * 7 + 2t * 7) + 3f = 55
(7 + 14t) + 3f = 55

Reorder the terms:
7 + 3f + 14t = 55

Solving
7 + 3f + 14t = 55

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + 3f + -7 + 14t = 55 + -7

Reorder the terms:
7 + -7 + 3f + 14t = 55 + -7

Combine like terms: 7 + -7 = 0
0 + 3f + 14t = 55 + -7
3f + 14t = 55 + -7

Combine like terms: 55 + -7 = 48
3f + 14t = 48

Add '-14t' to each side of the equation.
3f + 14t + -14t = 48 + -14t

Combine like terms: 14t + -14t = 0
3f + 0 = 48 + -14t
3f = 48 + -14t

Divide each side by '3'.
f = 16 + -4.666666667t

Simplifying
f = 16 + -4.666666667t

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