7(2t-4)=3(7t-)-8

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Solution for 7(2t-4)=3(7t-)-8 equation: 



7(2t-4)=3(7t-)-8

We move all terms to the left:

7(2t-4)-(3(7t-)-8)=0

We add all the numbers together, and all the variables

7(2t-4)-(3(+7t)-8)=0

We multiply parentheses

14t-(3(+7t)-8)-28=0



We calculate terms in parentheses: -(3(+7t)-8), so:

3(+7t)-8

We multiply parentheses

21t-8

Back to the equation:

-(21t-8)



We get rid of parentheses

14t-21t+8-28=0

We add all the numbers together, and all the variables

-7t-20=0

We move all terms containing t to the left, all other terms to the right

-7t=20

t=20/-7

t=-2+6/7

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