7(2v+3)+5v=2(4v+5)

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Solution for 7(2v+3)+5v=2(4v+5) equation: 



7(2v+3)+5v=2(4v+5)

We move all terms to the left:

7(2v+3)+5v-(2(4v+5))=0

We add all the numbers together, and all the variables

5v+7(2v+3)-(2(4v+5))=0

We multiply parentheses

5v+14v-(2(4v+5))+21=0



We calculate terms in parentheses: -(2(4v+5)), so:

2(4v+5)

We multiply parentheses

8v+10

Back to the equation:

-(8v+10)



We add all the numbers together, and all the variables

19v-(8v+10)+21=0

We get rid of parentheses

19v-8v-10+21=0

We add all the numbers together, and all the variables

11v+11=0

We move all terms containing v to the left, all other terms to the right

11v=-11

v=-11/11

v=-1

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