7(2x+1)=3(x+2)

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Solution for 7(2x+1)=3(x+2) equation: 



7(2x+1)=3(x+2)

We move all terms to the left:

7(2x+1)-(3(x+2))=0

We multiply parentheses

14x-(3(x+2))+7=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

14x-3x-6+7=0

We add all the numbers together, and all the variables

11x+1=0

We move all terms containing x to the left, all other terms to the right

11x=-1

x=-1/11

x=-1/11

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