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7(2x+1)=3(x+5)
We move all terms to the left:
7(2x+1)-(3(x+5))=0
We multiply parentheses
14x-(3(x+5))+7=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
14x-3x-15+7=0
We add all the numbers together, and all the variables
11x-8=0
We move all terms containing x to the left, all other terms to the right
11x=8
x=8/11
x=8/11
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