7(2x+10)=4(5-4x)-40

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Solution for 7(2x+10)=4(5-4x)-40 equation: 



7(2x+10)=4(5-4x)-40

We move all terms to the left:

7(2x+10)-(4(5-4x)-40)=0

We add all the numbers together, and all the variables

7(2x+10)-(4(-4x+5)-40)=0

We multiply parentheses

14x-(4(-4x+5)-40)+70=0



We calculate terms in parentheses: -(4(-4x+5)-40), so:

4(-4x+5)-40

We multiply parentheses

-16x+20-40

We add all the numbers together, and all the variables

-16x-20

Back to the equation:

-(-16x-20)



We get rid of parentheses

14x+16x+20+70=0

We add all the numbers together, and all the variables

30x+90=0

We move all terms containing x to the left, all other terms to the right

30x=-90

x=-90/30

x=-3

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