7(2x+18)=2(3x+35)

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Solution for 7(2x+18)=2(3x+35) equation: 



7(2x+18)=2(3x+35)

We move all terms to the left:

7(2x+18)-(2(3x+35))=0

We multiply parentheses

14x-(2(3x+35))+126=0



We calculate terms in parentheses: -(2(3x+35)), so:

2(3x+35)

We multiply parentheses

6x+70

Back to the equation:

-(6x+70)



We get rid of parentheses

14x-6x-70+126=0

We add all the numbers together, and all the variables

8x+56=0

We move all terms containing x to the left, all other terms to the right

8x=-56

x=-56/8

x=-7

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