7(2x+3)+4x=7+5(3x-4)+x

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Solution for 7(2x+3)+4x=7+5(3x-4)+x equation: 



7(2x+3)+4x=7+5(3x-4)+x

We move all terms to the left:

7(2x+3)+4x-(7+5(3x-4)+x)=0

We add all the numbers together, and all the variables

4x+7(2x+3)-(7+5(3x-4)+x)=0

We multiply parentheses

4x+14x-(7+5(3x-4)+x)+21=0



We calculate terms in parentheses: -(7+5(3x-4)+x), so:

7+5(3x-4)+x

determiningTheFunctionDomain
5(3x-4)+x+7

We add all the numbers together, and all the variables

x+5(3x-4)+7

We multiply parentheses

x+15x-20+7

We add all the numbers together, and all the variables

16x-13

Back to the equation:

-(16x-13)



We add all the numbers together, and all the variables

18x-(16x-13)+21=0

We get rid of parentheses

18x-16x+13+21=0

We add all the numbers together, and all the variables

2x+34=0

We move all terms containing x to the left, all other terms to the right

2x=-34

x=-34/2

x=-17

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