7(2x+3)+8(5x+1)=13(3x+5)+4(x+2)

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Solution for 7(2x+3)+8(5x+1)=13(3x+5)+4(x+2) equation: 



7(2x+3)+8(5x+1)=13(3x+5)+4(x+2)

We move all terms to the left:

7(2x+3)+8(5x+1)-(13(3x+5)+4(x+2))=0

We multiply parentheses

14x+40x-(13(3x+5)+4(x+2))+21+8=0



We calculate terms in parentheses: -(13(3x+5)+4(x+2)), so:

13(3x+5)+4(x+2)

We multiply parentheses

39x+4x+65+8

We add all the numbers together, and all the variables

43x+73

Back to the equation:

-(43x+73)



We add all the numbers together, and all the variables

54x-(43x+73)+29=0

We get rid of parentheses

54x-43x-73+29=0

We add all the numbers together, and all the variables

11x-44=0

We move all terms containing x to the left, all other terms to the right

11x=44

x=44/11

x=4

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