7(2x+3)-5=3(x+1)+6

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Solution for 7(2x+3)-5=3(x+1)+6 equation: 



7(2x+3)-5=3(x+1)+6

We move all terms to the left:

7(2x+3)-5-(3(x+1)+6)=0

We multiply parentheses

14x-(3(x+1)+6)+21-5=0



We calculate terms in parentheses: -(3(x+1)+6), so:

3(x+1)+6

We multiply parentheses

3x+3+6

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We add all the numbers together, and all the variables

14x-(3x+9)+16=0

We get rid of parentheses

14x-3x-9+16=0

We add all the numbers together, and all the variables

11x+7=0

We move all terms containing x to the left, all other terms to the right

11x=-7

x=-7/11

x=-7/11

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