7(2x+3)-8=2(x+2)-3x

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Solution for 7(2x+3)-8=2(x+2)-3x equation: 



7(2x+3)-8=2(x+2)-3x

We move all terms to the left:

7(2x+3)-8-(2(x+2)-3x)=0

We multiply parentheses

14x-(2(x+2)-3x)+21-8=0



We calculate terms in parentheses: -(2(x+2)-3x), so:

2(x+2)-3x

We add all the numbers together, and all the variables

-3x+2(x+2)

We multiply parentheses

-3x+2x+4

We add all the numbers together, and all the variables

-1x+4

Back to the equation:

-(-1x+4)



We add all the numbers together, and all the variables

14x-(-1x+4)+13=0

We get rid of parentheses

14x+1x-4+13=0

We add all the numbers together, and all the variables

15x+9=0

We move all terms containing x to the left, all other terms to the right

15x=-9

x=-9/15

x=-3/5

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