7(2x+3)/4=6(2x+5)/3

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Solution for 7(2x+3)/4=6(2x+5)/3 equation: 



7(2x+3)/4=6(2x+5)/3

We move all terms to the left:

7(2x+3)/4-(6(2x+5)/3)=0

We calculate fractions


14x/()+(-(6(2x+5)*4)/()=0



We calculate terms in parentheses: +(-(6(2x+5)*4)/(), so:

-(6(2x+5)*4)/(

We multiply all the terms by the denominator


-(6(2x+5)*4)



We calculate terms in parentheses: -(6(2x+5)*4), so:

6(2x+5)*4

We multiply parentheses

48x+120

Back to the equation:

-(48x+120)



We get rid of parentheses

-48x-120

Back to the equation:

+(-48x-120)



We get rid of parentheses

14x/()-48x-120=0

We multiply all the terms by the denominator


14x-48x*()-120*()=0

We add all the numbers together, and all the variables

14x-48x*()=0

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