7(2x+3)=11(3x-5)

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Solution for 7(2x+3)=11(3x-5) equation: 



7(2x+3)=11(3x-5)

We move all terms to the left:

7(2x+3)-(11(3x-5))=0

We multiply parentheses

14x-(11(3x-5))+21=0



We calculate terms in parentheses: -(11(3x-5)), so:

11(3x-5)

We multiply parentheses

33x-55

Back to the equation:

-(33x-55)



We get rid of parentheses

14x-33x+55+21=0

We add all the numbers together, and all the variables

-19x+76=0

We move all terms containing x to the left, all other terms to the right

-19x=-76

x=-76/-19

x=+4

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