7(2x+3)=9(x+4)

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Solution for 7(2x+3)=9(x+4) equation: 



7(2x+3)=9(x+4)

We move all terms to the left:

7(2x+3)-(9(x+4))=0

We multiply parentheses

14x-(9(x+4))+21=0



We calculate terms in parentheses: -(9(x+4)), so:

9(x+4)

We multiply parentheses

9x+36

Back to the equation:

-(9x+36)



We get rid of parentheses

14x-9x-36+21=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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