7(2x+4)=3(x-8)+7x

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Solution for 7(2x+4)=3(x-8)+7x equation: 



7(2x+4)=3(x-8)+7x

We move all terms to the left:

7(2x+4)-(3(x-8)+7x)=0

We multiply parentheses

14x-(3(x-8)+7x)+28=0



We calculate terms in parentheses: -(3(x-8)+7x), so:

3(x-8)+7x

We add all the numbers together, and all the variables

7x+3(x-8)

We multiply parentheses

7x+3x-24

We add all the numbers together, and all the variables

10x-24

Back to the equation:

-(10x-24)



We get rid of parentheses

14x-10x+24+28=0

We add all the numbers together, and all the variables

4x+52=0

We move all terms containing x to the left, all other terms to the right

4x=-52

x=-52/4

x=-13

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