7(2x+5)-4(x+2)-20x=3(x+3)-20x

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Solution for 7(2x+5)-4(x+2)-20x=3(x+3)-20x equation: 



7(2x+5)-4(x+2)-20x=3(x+3)-20x

We move all terms to the left:

7(2x+5)-4(x+2)-20x-(3(x+3)-20x)=0

We add all the numbers together, and all the variables

-20x+7(2x+5)-4(x+2)-(3(x+3)-20x)=0

We multiply parentheses

-20x+14x-4x-(3(x+3)-20x)+35-8=0



We calculate terms in parentheses: -(3(x+3)-20x), so:

3(x+3)-20x

We add all the numbers together, and all the variables

-20x+3(x+3)

We multiply parentheses

-20x+3x+9

We add all the numbers together, and all the variables

-17x+9

Back to the equation:

-(-17x+9)



We add all the numbers together, and all the variables

-10x-(-17x+9)+27=0

We get rid of parentheses

-10x+17x-9+27=0

We add all the numbers together, and all the variables

7x+18=0

We move all terms containing x to the left, all other terms to the right

7x=-18

x=-18/7

x=-2+4/7

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