7(2x+9)=3(1/5-x)

Solution for 7(2x+9)=3(1/5-x) equation:

7(2x+9)=3(1/5-x)

We move all terms to the left:

7(2x+9)-(3(1/5-x))=0


Domain of the equation: 5-x))!=0

We move all terms containing x to the left, all other terms to the right

-x))!=-5

x!=-5/1

x!=-5

x∈R


We add all the numbers together, and all the variables

7(2x+9)-(3(-1x+1/5))=0

We multiply parentheses

14x-(3(-1x+1/5))+63=0

We multiply all the terms by the denominator


14x*5))-(3(-1x+1+63*5))=0

We add all the numbers together, and all the variables

14x*5))-(3(-1x+316))=0

We add all the numbers together, and all the variables

-1x+14x*5))-(3(=0

Wy multiply elements

70x^2-1x=0

a = 70; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·70·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*70}=\frac{0}{140}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*70}=\frac{2}{140}
=1/70
$