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7(2x-1)(3x+4)=0
We multiply parentheses ..
7(+6x^2+8x-3x-4)=0
We multiply parentheses
42x^2+56x-21x-28=0
We add all the numbers together, and all the variables
42x^2+35x-28=0
a = 42; b = 35; c = -28;
Δ = b2-4ac
Δ = 352-4·42·(-28)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-77}{2*42}=\frac{-112}{84} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+77}{2*42}=\frac{42}{84} =1/2 $
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