7(2x-1)-3(4x-1)=4(3x+2)-2

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Solution for 7(2x-1)-3(4x-1)=4(3x+2)-2 equation: 



7(2x-1)-3(4x-1)=4(3x+2)-2

We move all terms to the left:

7(2x-1)-3(4x-1)-(4(3x+2)-2)=0

We multiply parentheses

14x-12x-(4(3x+2)-2)-7+3=0



We calculate terms in parentheses: -(4(3x+2)-2), so:

4(3x+2)-2

We multiply parentheses

12x+8-2

We add all the numbers together, and all the variables

12x+6

Back to the equation:

-(12x+6)



We add all the numbers together, and all the variables

2x-(12x+6)-4=0

We get rid of parentheses

2x-12x-6-4=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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