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7(2x-1)-3/5x=6/5(4-3x)
We move all terms to the left:
7(2x-1)-3/5x-(6/5(4-3x))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5(4-3x))!=0We add all the numbers together, and all the variables
x∈R
7(2x-1)-3/5x-(6/5(-3x+4))=0
We multiply parentheses
14x-3/5x-(6/5(-3x+4))-7=0
We calculate fractions
14x+(-15x(-)/(25x^2(-)+(-(6*5x)/(25x^2(-)-7=0
We can not solve this equation
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