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7(2x-1)=10-+5(2x+1)
We move all terms to the left:
7(2x-1)-(10-+5(2x+1))=0
We use the square of the difference formula
7(2x-1)-(10-5(2x+1))=0
We multiply parentheses
14x-(10-5(2x+1))-7=0
We calculate terms in parentheses: -(10-5(2x+1)), so:We get rid of parentheses
10-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+10
We multiply parentheses
-10x-5+10
We add all the numbers together, and all the variables
-10x+5
Back to the equation:
-(-10x+5)
14x+10x-5-7=0
We add all the numbers together, and all the variables
24x-12=0
We move all terms containing x to the left, all other terms to the right
24x=12
x=12/24
x=1/2
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