7(2x-1)=2(3x-2)-3(4x-3)+8

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Solution for 7(2x-1)=2(3x-2)-3(4x-3)+8 equation: 



7(2x-1)=2(3x-2)-3(4x-3)+8

We move all terms to the left:

7(2x-1)-(2(3x-2)-3(4x-3)+8)=0

We multiply parentheses

14x-(2(3x-2)-3(4x-3)+8)-7=0



We calculate terms in parentheses: -(2(3x-2)-3(4x-3)+8), so:

2(3x-2)-3(4x-3)+8

We multiply parentheses

6x-12x-4+9+8

We add all the numbers together, and all the variables

-6x+13

Back to the equation:

-(-6x+13)



We get rid of parentheses

14x+6x-13-7=0

We add all the numbers together, and all the variables

20x-20=0

We move all terms containing x to the left, all other terms to the right

20x=20

x=20/20

x=1

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