7(2x-1)=2(3x-2)-3(4x-3)+8

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Solution for 7(2x-1)=2(3x-2)-3(4x-3)+8 equation:



7(2x-1)=2(3x-2)-3(4x-3)+8
We move all terms to the left:
7(2x-1)-(2(3x-2)-3(4x-3)+8)=0
We multiply parentheses
14x-(2(3x-2)-3(4x-3)+8)-7=0
We calculate terms in parentheses: -(2(3x-2)-3(4x-3)+8), so:
2(3x-2)-3(4x-3)+8
We multiply parentheses
6x-12x-4+9+8
We add all the numbers together, and all the variables
-6x+13
Back to the equation:
-(-6x+13)
We get rid of parentheses
14x+6x-13-7=0
We add all the numbers together, and all the variables
20x-20=0
We move all terms containing x to the left, all other terms to the right
20x=20
x=20/20
x=1

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