7(2x-10)+10=4(3x-5)

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Solution for 7(2x-10)+10=4(3x-5) equation: 



7(2x-10)+10=4(3x-5)

We move all terms to the left:

7(2x-10)+10-(4(3x-5))=0

We multiply parentheses

14x-(4(3x-5))-70+10=0



We calculate terms in parentheses: -(4(3x-5)), so:

4(3x-5)

We multiply parentheses

12x-20

Back to the equation:

-(12x-20)



We add all the numbers together, and all the variables

14x-(12x-20)-60=0

We get rid of parentheses

14x-12x+20-60=0

We add all the numbers together, and all the variables

2x-40=0

We move all terms containing x to the left, all other terms to the right

2x=40

x=40/2

x=20

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