7(2x-10)+6x=10(5x-20)

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Solution for 7(2x-10)+6x=10(5x-20) equation: 



7(2x-10)+6x=10(5x-20)

We move all terms to the left:

7(2x-10)+6x-(10(5x-20))=0

We add all the numbers together, and all the variables

6x+7(2x-10)-(10(5x-20))=0

We multiply parentheses

6x+14x-(10(5x-20))-70=0



We calculate terms in parentheses: -(10(5x-20)), so:

10(5x-20)

We multiply parentheses

50x-200

Back to the equation:

-(50x-200)



We add all the numbers together, and all the variables

20x-(50x-200)-70=0

We get rid of parentheses

20x-50x+200-70=0

We add all the numbers together, and all the variables

-30x+130=0

We move all terms containing x to the left, all other terms to the right

-30x=-130

x=-130/-30

x=4+1/3

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