7(2x-10)-4=7(x-7)+3

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Solution for 7(2x-10)-4=7(x-7)+3 equation: 



7(2x-10)-4=7(x-7)+3

We move all terms to the left:

7(2x-10)-4-(7(x-7)+3)=0

We multiply parentheses

14x-(7(x-7)+3)-70-4=0



We calculate terms in parentheses: -(7(x-7)+3), so:

7(x-7)+3

We multiply parentheses

7x-49+3

We add all the numbers together, and all the variables

7x-46

Back to the equation:

-(7x-46)



We add all the numbers together, and all the variables

14x-(7x-46)-74=0

We get rid of parentheses

14x-7x+46-74=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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