7(2x-10)=63x

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Solution for 7(2x-10)=63x equation: 



7(2x-10)=63x

We move all terms to the left:

7(2x-10)-(63x)=0

We add all the numbers together, and all the variables

-63x+7(2x-10)=0

We multiply parentheses

-63x+14x-70=0

We add all the numbers together, and all the variables

-49x-70=0

We move all terms containing x to the left, all other terms to the right

-49x=70

x=70/-49

x=-1+3/7

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