7(2x-15)-28=35(1-x)-7

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Solution for 7(2x-15)-28=35(1-x)-7 equation: 



7(2x-15)-28=35(1-x)-7

We move all terms to the left:

7(2x-15)-28-(35(1-x)-7)=0

We add all the numbers together, and all the variables

7(2x-15)-(35(-1x+1)-7)-28=0

We multiply parentheses

14x-(35(-1x+1)-7)-105-28=0



We calculate terms in parentheses: -(35(-1x+1)-7), so:

35(-1x+1)-7

We multiply parentheses

-35x+35-7

We add all the numbers together, and all the variables

-35x+28

Back to the equation:

-(-35x+28)



We add all the numbers together, and all the variables

14x-(-35x+28)-133=0

We get rid of parentheses

14x+35x-28-133=0

We add all the numbers together, and all the variables

49x-161=0

We move all terms containing x to the left, all other terms to the right

49x=161

x=161/49

x=3+2/7

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